Question

ABC is a parallelogram in which angle A=110degree. find the measure of each of the angle of angle B,C,D​

Answer 1

Answer:

Given ∠A = 110o

But

we know that sum of adjacent angles of a parallelogram is 180o

∠A + ∠B = 180o

110o+ ∠B = 180o

∠B = 180o– 110o

= 70o.

Also ∠B + ∠C = 180o [Since ∠B and ∠C are adjacent angles]

70o+ ∠C = 180o

∠C = 180o– 70o= 110o.

Now ∠C + ∠D = 180o

110o+ ∠D = 180o

∠D = 180o– 110o

=70

Answer 2

Step-by-step explanation:

Given_A=110°

we know that opposite side of parallelogram are equal

so 2(a+b)=360

2(110+b)=360

b=70

similarly c=110(because opposite side are equal and parallel)

d=70(")