ABC is a quadrant if a circle of radius 14cm and a semicircle is drawn with BC. as diameter. find the area of shaded region
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r=14cm
r²+r²=hypotenuse²
2r²=hypotenuse²
2*196=hypotenuse²
392=hypotenuse²
14√2 = hypotenuse
Area of shaded region = area of semi circle - area of segment
= π(7√2)²/2-(2π*196*90/360-1/2*196*1)
=154- (308-98) cm²
=210-154 cm²
56 cm²
r²+r²=hypotenuse²
2r²=hypotenuse²
2*196=hypotenuse²
392=hypotenuse²
14√2 = hypotenuse
Area of shaded region = area of semi circle - area of segment
= π(7√2)²/2-(2π*196*90/360-1/2*196*1)
=154- (308-98) cm²
=210-154 cm²
56 cm²
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