Question

ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter find the area of the shaded region​

Answer 1

Step-by-step explanation:

area of quadrant=

$area \: of \: quadrant = \frac{\pi \times radius ^{2} }{4}$

$area = \frac{\pi \times 14 \times 14}{4} = 49\pi$

$area \: of \: shaded \: region \: = \\ area \: of \: quadrant - area \: of \: triangle.$

$area \: of \: triangle= \frac{1}{2} \times base \times height$

$area \: of \: triangle = \frac{1}{2} \times 14 \times 14 = 98 \: cm^{2}$

$area \: of \: shaded \: region = 49\pi - 98$

$area \: of \: shaded \: region = 55.93 \: cm^{2}$

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