Math, asked by kukku4079, 10 months ago

ABC is a rectangle E is the midpoint of AB prove that triangle d e c is an isosceles triangle hint prove using SAS Triangle AED parallel to triangle b e c

Answers

Answered by sankuvivek05
12

Answer:

given: ABCD is a rectangle

E Is the midpoint of side AB.

to prove: triangle DEC is isosceles.

proof: in triangles ADE and BCE

AD = BC (opposite sides of a rectangle )

WE =BE (E is the midpoint )

angles DAE and CBE are 90 degree (all angles in a rectangle are 90 degree )

therefore, triangles DAEand CBE are congruent (SAS congruence rule )

DE = CE (CPCT )

two sides are equal so triangle DEC is isosceles.

Answered by softwaretinka07
1

Answer:

given: ABCD is a rectangle

E Is the midpoint of side AB.

to prove: triangle DEC is isosceles.

proof: in triangles ADE and BCE

AD = BC (opposite sides of a rectangle )

WE =BE (E is the midpoint )

angles DAE and CBE are 90 degree (all angles in a rectangle are 90 degree )

therefore, triangles DAEand CBE are congruent (SAS congruence rule )

DE = CE (CPCT )

two sides are equal so triangle DEC is isosceles.

Step-by-step explanation:

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