Question

ABC is a right angied triangle, right angle at A. If AB=5cm,BC=12cm find AC​

Answer 1

Answer:

ABC is a right angled triangle

Therrefore,By Pythagoras Theorem

BC²=AB²+AC²

12²=5²+AC²

144 =25+AC²

AC ² =119

AC=√119 cm

Answer 2

In ΔABC,∠B=90°,AB = 5cm and BC = 12cm

By pythagoras theorem , we have

AC²= (AB²+BC²) = {(5)²+(12)²}cm²

=(25+144)cm²=169cm².

∴AC=$\sqrt{169 cm²}$ = 13cm

For T-ratios of ∠A, We have

Base = AB = 5cm,

Perpendicular =BC=12cm

Hypotenuse =AC=13cm.

∴sin A = BC/AC = 12/13

sec A = AC/AB = 13/5

for T-ratios of ∠C, we have

Base = BC = 12cm,

Perpendicular = AB = 5cm

Hypotenuse = AC = 13cm.

∴sin C = AB/AC = 5/13

sec C=AC/BC = 13/12.

Hope this answer helps you out .