Question

∆abc is a right angle ∆ in which angle a=90^0 and ab = ac . find angle b and angle c.

Answer 1

ABC is a right angles isosceles triangle
Therefore angle A = angle B
 Angle A + Angle B + Angle C = 180° 
2 (Angle A ) = 180 - 90
Angle A = 45°
Angle B = 45°

Answer 2

If AB=AC
Then angle B is equal to angle C
so by angle sum property
angleA + angleB +angleC=180°
90°+x+x=180°
2x=90°
x=45°
Hence Angle B and angle C will be equal to 45°
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