ABC is a right angle triangle at A and AD is the perpendicular to the hypotenuse.Then BD/CD is equal to
Answers
Answered by
1
Answer:
BC
2
=AB
2
+AC
2
BC
2
=AB
2
+(2AB)
2
=5AB
2
BC=
5AB
2
AB
2
=
5
BC
2
AC
2
=AD
2
+CD
2
AB
2
=AD
2
+BD
2
AC
2
−CD
2
=AB
2
−BD
2
BD
2
=AB
2
−AC
2
+CD
2
=AB
2
−4AB
2
+(BC−BD)
2
BD
2
=AB
2
−4AB
2
+BC
2
+BD
2
−2BC⋅BD
2BC⋅BD=−3AB
2
+5AB
2
2BC
B
¨
D=2AB
2
BD=
BC
AB
2
=
BC
BC/5
=
5
BC
⇒BD=
5
BC
.
Answered by
1
Answer:
BC
2
=AB
2
+AC
2
BC
2
=AB
2
+(2AB)
2
=5AB
2
BC=
5AB
2
AB
2
=
5
BC
2
AC
2
=AD
2
+CD
2
AB
2
=AD
2
+BD
2
AC
2
−CD
2
=AB
2
−BD
2
BD
2
=AB
2
−AC
2
+CD
2
=AB
2
−4AB
2
+(BC−BD)
2
BD
2
=AB
2
−4AB
2
+BC
2
+BD
2
−2BC⋅BD
2BC⋅BD=−3AB
2
+5AB
2
2BC
B
¨
D=2AB
2
BD=
BC
AB
2
=
BC
BC/5
=
5
BC
⇒BD=
5
BC
.
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