Question

ABC is a right angle triangle at a and sides ab bc and ac are the tangents to the circle with the centre of as shown in the figure if a b is equal to 6 CM BC is equal to 8 cm find the area of the shaded region

Answer 1

Answer:

24-4π cm sq

11.44 sq cm

Step-by-step explanation:

${ac}^{2} = {ab}^{2} + {bc}^{2} \\ {ac}^{2} = {6}^{2} + {8}^{2} \\ {ac}^{2} = 100 \\ ac = 10$

area of triangle abc = (1/2)*6*8= 24

area of triangle abc = area of triangle aob + triangle aoc + triangle boc

24 = (1/2)r(6+8+10)

r =2

area of circle= π2*2 = 4π

area of shaded region = 24-4π cm sq

11.44 sq cm