Question

ABC is a right angle triangle at B. AD and CE are two medians from the vertices A and C respectively . If length of CE = 2√5 cm and length of AC = 5 cm ,what is the length of AD?

Answer 1

AC=5 and ABC is a right angle triangle. so we can safely assume that it is a triplet ,i.e 3
${3 }^{2} + 4 {}^{2} = 5 {}^{2}$
B= 90 degree. A= 3 cm , BD= 4/2=2 =>
$\sqrt{(3} {}^{2} + {2}^{2} ) = \sqrt{(13)}$