abc is a right angle triangle at c . ac =root3bc. find the value of angle b
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Answer:
Given: △ABC is right angled at C and AC = √3BC.
To prove: ∠ABC = 60°.
Proof:
Let D be the midpoint of AB. Join CD.
Now, AB2 = BC2 + AC2 = BC2 + (√3BC)2 = 4BC2
Therefore AB = 2BC.
Now, BD = 1/2 AB = 1/2(2BC) = BC.
But, D being the midpoint of hypotenuse AB, it is equidistant from all the
three vertices.
Therefore CD = BD = DA or CD = 1/2 AB = BC.
Thus, BC = 80 = CD,
i.e., △BCD is a equilateral triangle.
Hence, ∠ABC = 60°.
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