Question

ABC is a right angle triangle at C and m is midpoint of ab and MD parallel BC prove that CM=ma=1/2ab
please give me answer
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Answer 1

Answer:

In ∆ABC, we have

M is the midpoint of AB and MD||BC

D is the midpoint of AC {by converse of midpoint theorem}

Now

MP||BC

<MDC+<BCD=180°

<MDC+90°=180°

<MDC=90°

Thus;MD perpendicular AC

Join MC

In ∆MDA and ∆MDC we have

DA=DC

<MDA=<CDM

MD=MD

∆MDA~∆MDC {S.A.S}

And so MA=MC

Now M is the midpoint of AB

MA=MC=1/2AB

Step-by-step explanation: sorry no figure