Question

ABC is a right angle triangle.
BP is a perpendicular to hypotenuse AC.
Prove that triangle ABC is congruent to triangle ABP is congruent to triangle CBP.

The figure is given above. Please help. ​

Answer 1

Answer:

Given,

ABC is a right angled triangle.

BP | AC

We have to prove that,

ABC≈ABP≈CBP

Step-by-step explanation:

ANGLE ABC=APB ( 90° )

AB = AB ( COMMON )

BC = BP

HENCE ABC ≈ABP ......

NOW,

a/q

We have to prove that,

ABP ≈ CBP

CPB = ABP ( 90 ° )

BC = AB

PB = PB ( COMMON )

Therefore , ABC≈ABP≈CBP ..... proved ...