ABC is a right angle triangle. Find the length of the side CB.
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Answered by
0
Step-by-step explanation:
Let the point C be (h,K)
and A≡(l,0),B≡(0,m)
Slope of AC=
h−l
k
⟶(1)
Slope of BC=
h
K−m
⟶(2)
Using distance formula,
a=
(h−l)
2
+K
2
⇒h−l=
a
2
−K
2
⟶(3)
Similarly
K−m=
b
2
−h
2
⟶(4)
Slope of AC=
a
2
−K
2
K
Slope of BC=
h
b
2
−h
2
Since AB is perpendicular to BC
∴
a
2
−K
2
K
.
h
b
2
−h
2
=−1
Squaring both sides we get
a
2
−K
2
K
2
=
b
2
−h
2
h
2
(b
2
−h
2
)K
2
=h
2
(a
2
−K
2
)
bK±ah=0
Hence locus of point C is
ax±by=0
Answered by
0
Answer:
It is clearly visible that this is a right-angled triangle
Step-by-step explanation:
Now if you know Pythagoras theorem
but still it is
p^2 + b^2 = h^2
where,
p=height
b=base
h=hypothenuse
let p and b be x
x^2 + x^2 = 12 ^2
=>2x^2=144
=>2x=12
=>x=6
please mark me as the brainliest
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