ABC is a right angle triangle right angle at B. D is the midpoint of AC. AB =3cm and BC =4cm what is the length of BD
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by pythagorus theorum:-(ab)^2+(bc)^2=(ac)^2
so, (4cm)^2+(3cm)^2=(ac)^2
16cm^2+9cm^2=(ac)^2
25cm^2=(ac)^2
square root 25cm^2 will be 5cm.
REMEMBER ^ THIS SIGN SHOWS POWER OVER NUMBER.
so, (4cm)^2+(3cm)^2=(ac)^2
16cm^2+9cm^2=(ac)^2
25cm^2=(ac)^2
square root 25cm^2 will be 5cm.
REMEMBER ^ THIS SIGN SHOWS POWER OVER NUMBER.
Answered by
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Answer:
by pythagorus theorum:-(ab)^2+(bc)^2=(ac)^2
so, (4cm)^2+(3cm)^2=(ac)^2
16cm^2+9cm^2=(ac)^2
25cm^2=(ac)^2
square root 25cm^2 will be 5cm.
REMEMBER ^ THIS SIGN SHOWS POWER OVER NUMBER.
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