Question

ABC is a right angle triangle right angled at B then prove sin square C + cos square C is equals to 1​

Answer 1

Answer:

Hey mate, Good morning ♡

# Here's ur answer ♤♡◇♧

Step-by-step explanation:

Hope it helps u...○●□■ Practice more...It was a good question ☆☆☆

Answer 2

QUESTION

ABC is a right triangle right angled at B , then prove

sin²C + cos²C = 1.

SOLUTION

refer to the attachment for the figure of triangle

we have to prove

sin²C + cos²C = 1

KNOWING THAT

sin θ = opposite side / hypotenuse

and

cos θ = adjacent side / hypotenuse

also, IN right triangle ABC by pythagoras

we have, AB² + BC² = AC²  -----eqn (1)

taking LHS

LHS = sin²C + cos²C

= (AB / AC)² + (BC/AC)²

$= \frac{AB^2}{AC^2} + \frac{BC^2}{AC^2} \\\\( taking\:LCM)\\\\=\frac{AB^2+BC^2}{AC^2}\\\\(by\:eqn\:(1))\\\\=\frac{AC^2}{AC^2} = 1 = RHS$

LHS = RHS

hence proved.