∆ABC is a right angle triangle
where Angle ABC is right angle
and
Where BD perpendicular to AC
PROVE THAT :-
AB^2 ×BC^2 =BD^2 ×AC^2
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hence proved. . .. . .
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SumitKar:
Its wrong
Ive proved it , its not wrong , the method is different thats it .
no ayar
it to simple
Ive just followed the other method
its by triangle area
Ive edited
right
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