ABC is a right angle triangle with angle ACB is equal to 90 degree BC equal to 12 CM AB equal to 15 cm and CD equal to 5 cm find the lengths of BD and AD
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Answer:
Step-by-step explanation:
First find AB
using pythagoras theorem. As per your question
AB2=AC2+BC2
AB2=162+122
AB2=256+144
AB2=400
AB=20
Now find the area of triangle ABC,
base×height2
12×162
Area=96
unit2
Now as CD is perpendicular to AB, take AB as base and CB as height. The area is known so height can be found.
AB×CD2=96
20×CD2=96
CD=96×220
CD=9.6
HOPE IT WAS HELPFUL
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