Question

ABC is a right angle triangle, with ∠B = 90°. If (AB - BC)2 = 2BC(AC - BC), then ∠C =

Answer 1

Answer:

60 deg

Step-by-step explanation:

with correction in question

(AB - BC)^2 = 2BC(AC - AB)

AB^2 + BC^2 -2AB.BC = 2BCAC-2BCAB

AB^2 + BC^2 -2AB.BC = 2BCAC-2AB.BC

cancelling 2AB.BC from both sides

AB^2 + BC^2 = 2BCAC

using AB^2 + BC^2 = AC^2

AC^2 = 2BC.AC

dividing by AC both sides

AC = 2 BC

1/2 = BC/AC

1/2 = CosC

C = 60 deg

Answer 2

Answer:

60 deg

Step-by-step explanation:

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