Question

△ABC is a right angled at A. Q and R are points on BC produced and BC respectively. There is a point P such that QP is parellel to AB and RP is parellel to AC . Find angle P.

Answer 1

$\textbf{ Hello Mate! }$

Given : < A = 90°

To Find : < P

Solution : Since AC || PS where AB is transversal.

< BAC = < BSR [Corresponding angles]

< BSR = 90°

Since PQ || AB where PS is transversal.

< BSR = < RPQ [Alternate angles]

< RPQ = 90°

$\textsf{ Answer : 90° }$

Have great future ahead!

Answer 2

Step-by-step explanation:

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