∆ABC is a right angled triangle. AB= BC, D and F are the midpoints of AB and BC respectively. DE||BC, M and N are the midpoints of DE and BF respectively. AB = 24. Find the area of ∆DMO.
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ab = 24
ab= bc.
de=1/2 bc (mid point theorm)
de=12
ef=1/2ab
ef=1/224
ef=12
mn is parallel to ef so it is also 12
mo = 6 and dm = bcz it is half of mn and de respectively.
now to find are of dmo we need length of and om bcz area of triangle=1/2 ×dm×om
= 1/2×6×6
= 1/2×36
=36/2
=18 unit.
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