Question

ABC is a right angled triangle AB is equal to 6 and BC is equal 8 how much is the hypotenuse AC​

Answer 1

Answer:

AB, BC and CA are tangents to the circle at P, N and M.

∴ OP = ON = OM = r (radius of the circle)

By Pythagoras theorem,

CA2 = AB2 + BC2

⇒ CA2 = 82 + 62

⇒ CA2 = 100

⇒ CA = 10 cm

Area of ∆ABC = Area ∆OAB + Area ∆OBC + Area ∆OCA

Answer 2

Answer:

Ac=10

Step-by-step explanation:

It's Correct...

hope it helps ...!!