ABC is a right angled triangle and o is mid point of the side opposite to the right angle. Explain why O is equidiatant from A,B,C
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I'll try to explain..
a circle can be constructed through any 3 given points. so if we construct a circle around the triangle using its 3 vertices.... then the hypotenuse will be the diameter... (the diameter subtends a right angle at any point on the circumference)
hence, half the hypotenuse is the radius
therefore, the point O ( the centre of the circle) will be equidistant to all points a,b,c as th lie on the circumference.
Hope it was helpful!! if u still didnt understand pls comment☺
a circle can be constructed through any 3 given points. so if we construct a circle around the triangle using its 3 vertices.... then the hypotenuse will be the diameter... (the diameter subtends a right angle at any point on the circumference)
hence, half the hypotenuse is the radius
therefore, the point O ( the centre of the circle) will be equidistant to all points a,b,c as th lie on the circumference.
Hope it was helpful!! if u still didnt understand pls comment☺
701Disha191:
Mark it as brainliest if it was helpful!!!
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