Question

ABC is a right-angled triangle and O is mid-point of the side opposite to right angle. Prove that O is equidistant from A,B and C​

Answer 1

Answer:

If b = 45°

it is equidistant to point a, b and c

Answer 2

Step-by-step explanation:

Draw lines AD and DC such that AD ||BC ,

ABIIDC AD = BC , AB = DC

ABCD is a rectangle as opposite sides are equal

and parallel to each other and all the interior angles are of 90 degrees

In a rectangle, diagonals are of equal length and also these bisect each other.

Hence, AO=OC=BO=OD

Thus, O is equidistant from A, B, and C.