Math, asked by gkritika545, 1 month ago

ABC is a right-angled triangle and O is mid-point of the side opposite to right angle. Prove that O is equidistant from A,B and C​

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Answered by kinghacker
19

Between ∆ AOD & ∆ BOC we have AO = CO (given),BO=OD(by Const-ruction).

\angle AOD=  \angle BOC... \\  Vertically  \: opposite

angle

.. By SAS test ∆AOD &∆ BOC are congr-uent.

So AD=BC....(i)

similarly, between ∆ AOB & ∆ DOC we have AO = CO (given), BO = OD (by Constr-uction)

 \angle AOB=  \angle DOC ... </p><p></p><p>

sorry. see the attachment

it not allowed

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Answered by Anonymous
4

Answer:

ABC is the right Answer ✌️

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