ABC is a right-angled triangle and O is mid-point of the side opposite to right angle. Prove that O is equidistant from A,B and C
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Between ∆ AOD & ∆ BOC we have AO = CO (given),BO=OD(by Const-ruction).
angle
.. By SAS test ∆AOD &∆ BOC are congr-uent.
So AD=BC....(i)
similarly, between ∆ AOB & ∆ DOC we have AO = CO (given), BO = OD (by Constr-uction)
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