Abc is a right angled triangle. Bac = 90o and acb = 60o. What is the ratio of the circum radius of the triangle to the side ab?
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Answer:
Ratio of circum radius to side of triangle = 1:√3
Step-by-step explanation:
∠ABC = 30°
Midpoint of CB is centre of the Circumcircle i.e. bc = 2r.
sin60° = AB/BC
√3/2 = AB/2r.
r/AB = 1/√3.
Ratio of circum radius to side of triangle = 1:√3
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