Question

ABC is a right-angled triangle find
(iii) the length of BD correct to two places of decimal.

So I want the process for the last one which I have typed it down over here for your convenience..please help me out ( Ans 8.78 cm ) Please provide a simple procedure for class 7 th .. Wrong process shall be reported
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Answer 1

Step-by-step explanation:

ANSWER

REF.Image

AC2=AB2+BC2

AC2=242+72

AC = 26

area ΔABC=21×24×7=84

BD2=(24)2−(AD)2

(BC)2=BD2+(CD)2

(BC)2=(24)2−(AD)2+(CD)2

49=(24)2−(AD)2+(AC−AD)2

49=(24)2−AD2+(AC−AD)2

49=(24)2−AD2+AC2+AD2−2ACAD

49=576+676−26AD

26×2AD=