Abc is a right angled triangle in which a = 90, ab = 5 cm and ac = 12 cm. What is the approximate volume (in cm3) of the double cone formed by rotating the triangle about its hypotenuse?
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Answer:
area of triangle = (1/2) × base×height
if we take AC as perpendicular then AB will be base.
then area of triangle = (1/2)× 5×12 = 30 cm²
also, by Pythagoras' theorem,
BC² = AC² +AB²
=12² + 5² = 169
⇒BC = 13 cm
now, if AD is perpendicular then BC is the base
area of triangle = (1/2)× BC ×AD
⇒30 = (1/2)× 13×AD
⇒AD = 60/13 =4.61 cm
Hope it helps you...
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