Question

∆ABC is a right angled triangle in which A= 90° AB=AC find the value of angles A and B​

Answer 1

Answer:

ANSWER

Since AB=AC, 

So, △ABC is Right-angled isosceles.

∠B=∠C             ...(angles opp. to equal sides are equal)

∠A+∠B+∠C=180∘       ...(angle - sum property of a triangle)

Substituting ∠B=∠C, ∠A=90o

90∘+2∠B=180∘ 

2∠B=180∘–90∘=90∘

⇒∠B=45∘

So, ∠C=∠B=45o.

Answer 2

Step-by-step explanation:

given AB=AC

angle A is already give i.e, 90°

∆ABC is an equilateral right angle triangle .

so , angle(B)=angle(C)

by triangle property,

angle(A) + angle(B) + angle(C) = 180

90 + 2*angle(B)=180

2*angle(B)=180-90

angle(B)= 90/2

angle(B) =45°

also angle(C)=45°