Question

ABC is a right angled triangle in which angle A= 90°
and AB=AC. Find angle B and angle C.

#Nospamming. ​

Answer 1

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IN TRIANGLE ABC

A = 90°

since

AB = AC

SO .....

angle B = angle C _________(1) ( front angle of equal side)

in triangle. ABC

< A + < B + < C = 180°

<A +<A +90° = 180° { from eq.(1)}

2 <A = 90°

<A = < B = 45°

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Answer 2

Given :

• ∠A = 90°
• AB = AC

To Find :

• ∠B and ∠C

Solution :

In Δ ABC :

$\longmapsto\tt{AB=AC}$

$\longmapsto\tt{\angle{B}=\angle{C}\:(Angles\:opp.\:to\:equal\:sides)}$

Now ,

$\longmapsto\tt{\angle{A}+\angle{B}+\angle{C}=180\degree\:(A.S.P)}$

$\longmapsto\tt{90\degree+\angle{B}+\angle{B}=180\degree}$

$\longmapsto\tt{90\degree+2\angle{B}=180\degree}$

$\longmapsto\tt{2\angle{B}=180\degree-90\degree}$

$\longmapsto\tt{2\angle{B}=90\degree}$

$\longmapsto\tt{\angle{B}=\cancel\dfrac{90}{2}}$

$\longmapsto\tt\bf{\angle{B}=45\degree}$

Therefore :

$\longmapsto\tt\bf{Measure\:of\:\angle{B}=45\degree}$

$\longmapsto\tt\bf{Measure\:of\:\angle{C}=45\degree}$