Abc is a right angled triangle right angled at
a. A circle is inscribed in it. The lengths of two sides containing the right angle are 6 cm and 8cm
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Consider ABC be the right angled triangle such that ∠A = 90° and AB = 6cm AC = 8cm
And O be the centre and r be the radius of the incircle.
AB, BC and CA are tangents to the circle at P, N and M.
∴ OP = ON = OM = r (radius of the circle)Area of ΔABC = ½ × 6×8=48 cm2
By Pythagoras theorem,
BC2 = AC2 + AB2
⇒ BC2 = 62 +82
BC2 = 100
BC = 10 cm
make sure it brainliest please
hope you like this answer
Consider ABC be the right angled triangle such that ∠A = 90° and AB = 6cm AC = 8cm
And O be the centre and r be the radius of the incircle.
AB, BC and CA are tangents to the circle at P, N and M.
∴ OP = ON = OM = r (radius of the circle)Area of ΔABC = ½ × 6×8=48 cm2
By Pythagoras theorem,
BC2 = AC2 + AB2
⇒ BC2 = 62 +82
BC2 = 100
BC = 10 cm
make sure it brainliest please
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