Question

ABC is a right angled triangle, right angled at B, AD &CE are two median drawn from A & C respectively. If AC =5cm, AD=3root5/2 cm then find the length of CE

Answer 1

As

4(AD²+CE²) =5AC²

4(45/4 + CE²) =5*5*5

45+4*CE²=125

4CE²=125-45

CE²=80/4

CE²=20

CE=√20