Question

∆ABC is a right angled triangle right angled at B prove that sin² Q + Cos² Q = 1​

Answer 1

Answer:

Let a, b, c be lengths of right angled triangle

By definition

sinθ=b/c(

hypotenuse

opposite side

)

cosθ=a/c(

hypotenuse

adjacent side

)

sin

2

θ+cos

2

θ=

c

2

b

2

+

c

2

a

2

=

c

2

a

2

+b

2

From Pythagoras theorem

c

2

=a

2

+b

2

∴

c

2

a

2

+b

2

=1

sin

2

θ+cos

2

θ=1

Hence, proved.

Step-by-step explanation:

I'm not really good at maths but hope this helps Army

Answer 2

Answer:

Applying Pythagoras theorem for ΔABC, we obtain

AC2 = AB2 + BC2

= (24 cm)2 + (7 cm)2

= (576 + 49) cm2

= 625 cm2

∴ AC =√625 cm = 25 cm