ABC Is a right angled triangle rt angled at B with hypotenuse AC=26cm and perimeter 60cm Calculate the area of the triangle and the other two sides.
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Area is to be found by Heron Formula.
√s(s-a) (s-b) (s-c)
Perimeter = Sum of 3 sides
60=26 + AB + BC
AB + BC = 34
AB = 34 - BC
AB^2 +BC^2 = 26^2
(34-BC) ^2 +BC ^2 =576
34x34 +BC ^2 -2 x BC x34 +BC^2 =576
2 BC^2-68BC =576-1296
2BC^2 -68BC-720=0
Find BC and AB
√s(s-a) (s-b) (s-c)
Perimeter = Sum of 3 sides
60=26 + AB + BC
AB + BC = 34
AB = 34 - BC
AB^2 +BC^2 = 26^2
(34-BC) ^2 +BC ^2 =576
34x34 +BC ^2 -2 x BC x34 +BC^2 =576
2 BC^2-68BC =576-1296
2BC^2 -68BC-720=0
Find BC and AB
Answered by
0
Answer:Use Pythagoras Theorem AB^2 + BC^2 = AC^2 AB^2 + 100 = 676 AB^2 = 576 AB = 24
Step-by-step explanation:
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