Δabc is a right angled triangle, the radius of its circumcircle is 3 cm and the length of its altitude drawn from the opposite vertex to the hypotenuse is 2 cm. then the area of the triangle is
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Let ABC be the right angled triangle right angled at B.Let O be the centre of circle. O is the mid point of hypotenuse by geometry
OA= OB = OC = radius of the circumcircle = 3 cm
Hypotenuse AC= Diameter of circle =2 × radius of circumcircle=2×3=6 cm
Let be the perpendicular from B on AC
BM = 2 cm
area of right angle ∆= 1/2 ×B×H
=1/2×6×2 = 6 cm²
OA= OB = OC = radius of the circumcircle = 3 cm
Hypotenuse AC= Diameter of circle =2 × radius of circumcircle=2×3=6 cm
Let be the perpendicular from B on AC
BM = 2 cm
area of right angle ∆= 1/2 ×B×H
=1/2×6×2 = 6 cm²
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