Math, asked by Aniket1338, 1 year ago

Δabc is a right angled triangle, the radius of its circumcircle is 3 cm and the length of its altitude drawn from the opposite vertex to the hypotenuse is 2 cm. then the area of the triangle is

Answers

Answered by MOSFET01
0
Let ABC be the right angled triangle right angled at B.Let O be the centre of circle. O is the mid point of hypotenuse by geometry

OA= OB = OC = radius of the circumcircle = 3 cm

Hypotenuse AC= Diameter of circle =2 × radius of circumcircle=2×3=6 cm

Let be the perpendicular from B on AC

BM = 2 cm

area of right angle ∆= 1/2 ×B×H

=1/2×6×2 = 6 cm²
Answered by Anonymous
3

 \\  \boxed{ \rm \: let \:  \triangle \: abc \: be \: right \: angled \: at \: B}

 \textsf{Then hypotenus \: AC = diameter \: of \: its \: circumcircle}

 \textsf{ = (2 × 3) = 6cm}

 \textsf{Let BL⏊AC  .Then,BL=2cm}

 \textsf{Area of triangle ABC}= \rm \huge {\frac{1}{2}}  \small ×AC×BL

 \rm = \large  \big(   \frac{1}{2}  \times 3 \times 2 \big)cm {}^{2}  = 6cm {}^{2}

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