ABC is a right-angled triangle whose hypotenuse is AC. If AB : BC = 3 : 4, then the smallest angle of the triangle is :
a)∠A
b)∠B
c)AB
d)∠C
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ANSWER
Given :-
ABC is a right-angled triangle whose hypotenuse is AC. If AB : BC = 3 : 4, then the smallest angle of the triangle
Solution:-
If Perpendicular and base are in 3 : 4
then Let Hypotenuse be x
x² = 3² + 4² ( For right condition )
● x² = 9 + 16
● x² = 25
● x² = 5 × 5
● [ x = 5 ]
The triangles are
Angle AB = 3x ( Base )
Angle BC = 4x ( Perpendicular)
Angle AC = 5x ( Hypotenuse)
FINAL ANSWER
Therefore as we know 3x is smallest
So; 3x can be considered as smallest
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