Question

Abc is a right-angled triangle with angle b = 90 degrees, ab = 12 cm and ac = 13 cm. A circle with center o is inscribed inside the triangle, find the radius of the circle

Answer 1

according to phytogoras

hypotenos^2 =base^2+perpendicular^2

ac^2=ab^2 +bc^2

13^2=12^2+bc^2

169=144+bc^2

169-144=bc^2

bc^2 =25

$bc = \sqrt{25}$

$bc = \sqrt{5 \times 5}$

$bc = 5$

and bc = dia