ABC is a right angled triangle with angle b = 90°, ab=8cm and ac=10cm. find sin A, cos A, sin C and cos C
Answers
Answered by
1
Step-by-step explanation:
AB=8 cm
AC=10 cm
so, BC=√(10^2-8^2) cm
=√(100-64) cm
=√36 cm
=6cm
sin A=BC/AC=6/10=3/5
sin C=AB/AC=8/10=4/5
cosA=AB/AC=8/10=4/5
cosC=BC/AC=6/10=3/5
Answered by
3
Answer:
Step-by-step explanation:
By Pythagoras
BC=6cm
SinA=opp/hypo=3/5
SinC=oppj/hypo=4/5
CosA=adj/hypo=4/5
CosC=adj/hypo=3/5
Pls verify
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