Abc is a right angled triangle with angle bac = 90. Ah is drawn perpendicular to bc. If ab = 60 cm and
Answers
Answered by
0
Answer:
plz give the full question
Answered by
0
Answer:
Consider \triangle△ ABCABC and \triangle△ BAHBAH
\cos(\angle ABC)=\dfrac{AB}{BC}cos(∠ABC)=
BC
AB
(\because \triangle ABC∵△ABC is a right angled triangle and from definition of cos)
\cos(\angle ABH)=\dfrac{BH}{AB}cos(∠ABH)=
AB
BH
(\because \triangle ABH∵△ABH is a right angled triangle and from definition of cos)
\angle ABC=\angle ABH∠ABC=∠ABH
\Rightarrow \dfrac{AB}{BC}=\dfrac{BH}{AB}⇒
BC
AB
=
AB
BH
\Rightarrow BH=\dfrac{AB\times AB}{BC}=\dfrac{60\times 60}{100}=36⇒BH=
BC
AB×AB
=
100
60×60
=36 cm
Similar questions