Abc is a right angled triangle with bac = 90. Ad is drawn perpendicular to bc. If ab = 60 cm and ac = 80 cm, then find the length of bh.
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Answer:
Step-by-step explanation:
Here hypotenuse BC = 100 cm (by Pythagorean Triplet)
AH = (80×60)÷100 cm
=48 cm
If Perpendicular AH is drawn on Hypotenuse BC, AH will be Perpendicular of ∆ABH, AB will be Hypotenuse and BH will be the base of ∆ABH
So, the Base BH^2 = AB^2-AH^2
= (60^2-48^2)cm
= (3600-2304)cm
=1296cm
BH=√1296cm
=36cm
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