ABC is a right angled triangle with BAC=90 .AH is drawn perpendicular to BC. If AB =60 AND AC=80cm then find the length of BH.
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Given ABC is a right angled triangle,
By phythagorous theorem
AB^2+AC^2=BC^2
60^2+80^2=BC^2
3600+6400=BC^2
10000=BC^2
BC=100
Given AH is perpendicular (median),
BH=CH=BC/2
Therefore BH is 100/2=50
By phythagorous theorem
AB^2+AC^2=BC^2
60^2+80^2=BC^2
3600+6400=BC^2
10000=BC^2
BC=100
Given AH is perpendicular (median),
BH=CH=BC/2
Therefore BH is 100/2=50
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