ABC is a right angled triangle with hypotenuse AC = 13 cm and side AB = 5 cm. Perpendiculars are drawn from mid-point M of AC to AB and BC. What is the perimeter of the resulting quadrilateral?
Answers
Answered by
20
Answer:
The answer is 17 cm
Step-by-step explanation:
The lenth of BC is root (13 square-5 Square) =ROot144 =12 cm
If The line from M drawn to P point in AB and to the point QIn BC
Then MP=1/2 of BC =6 cm
As the same way MQ=1/2AB =5/2cm
Now the perimmeter of BPMQ is 5/2+5/2+6+6=17 cm
Hope you like
Answered by
4
Answer:
17 cm is answer for the question
Similar questions