ABC is a right angled triangle with
perpendicular to AC. Prove that (1) AADE ~ AACB
(ii) If AC = 13 cm, BC-5cm and AE=4cm, find DE and AD
(iii) Find, area of AADE : area of quad BCED
elainajudu:
please give a proper answer
Answers
Answered by
2
To Prove : △ADE∼△ACB
Proof :
(i) In △ADE and △ACB
(1) ∠A=∠A [common]
(2) ∠AED=∠ABC=90
o
(given)
∴ △ADE∼△ACB [AA axiom]
it is only half answer only 1 answer i type only
ok
Similar questions