Question

ABC is a right angled triangle with perpendicular to AC. Prove that (1) AADE ~ AACB
(ii) If AC = 13 cm, BC-5cm and AE=4cm, find DE and AD
(iii) Find, area of AADE : area of quad BCED

Answer 1

To Prove : △ADE∼△ACB

Proof :

(i) In △ADE and △ACB

(1) ∠A=∠A [common]

(2) ∠AED=∠ABC=90

o

(given)

∴ △ADE∼△ACB [AA axiom]