abc is a right triangle and right angled at b ad and ce are 2 medians from a and c respectively if ac=5 cm and ad=3 root 5 cm find the length of ce
Answers
Answered by
2
See diagram.
AC = 5 cm. AD = 3 cm.. if AD = 3√5 cm then it is wrong,, as AD < AC. AC is the longest line segment in the triangle ABC.
let BD = x, BC = 2 x, AE = y, AB = 2 y
AD² = AB² + BD² = 4 y² + x² = (3)² = 9 cm² ---- (1)
AC² = AB² + BC² => 4 y² + 4 x² = 5² = 25 cm² ---- (2)
(2) - (1) => 3 x² = 16 => x = 4/√3 cm
=> y = √(11/12) cm
CE² = BC² + BE² = (2x)² + y² = 4 x² + y² = 64/3 + 11/12 = 69/4 cm²
CE = √69/2 cm
Since ABC is a right angle triangle, BF = BE/2 = CE / 2 = 2.5 cm
So BO = 2*2.5/3 = 5/3 cm and OE = 2.5/3 cm
AC = 5 cm. AD = 3 cm.. if AD = 3√5 cm then it is wrong,, as AD < AC. AC is the longest line segment in the triangle ABC.
let BD = x, BC = 2 x, AE = y, AB = 2 y
AD² = AB² + BD² = 4 y² + x² = (3)² = 9 cm² ---- (1)
AC² = AB² + BC² => 4 y² + 4 x² = 5² = 25 cm² ---- (2)
(2) - (1) => 3 x² = 16 => x = 4/√3 cm
=> y = √(11/12) cm
CE² = BC² + BE² = (2x)² + y² = 4 x² + y² = 64/3 + 11/12 = 69/4 cm²
CE = √69/2 cm
Since ABC is a right angle triangle, BF = BE/2 = CE / 2 = 2.5 cm
So BO = 2*2.5/3 = 5/3 cm and OE = 2.5/3 cm
Attachments:
kvnmurty:
click on thanks button above please
Similar questions