ABC is a right triangle and right angled at B such that ∠BCA = 2∠BAC. Show that
AC=2BC
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Triangle ABC is a right angled triangle at angle B .......given
Angle B=90degrees
let angle BAC=x degrees
then angle BCA=2x degrees
thus,
angle B+ angle BAC+ angle BCA= 180degrees .........sum of angles of triangle
90+x+2x=180
90+3x=180
3x=180-90
3x=90
dividing both sides by 3
x=30
then
angle BAC=30degrees and angle BCA=2(30)=60degrees
therefore the measures of angles of triangle ABC are 30,60 and 90 degrees
here side AC is a hypotenuse
therefore
in 30-60-90 triangle
side opposite to 30degrees is half the hypotenuse
here the side opposite to 30 degrees is side BC
therefore
BC=1/2*AC
thus
2BC=AC
thus
AC=2BC
please forgive if there are mistakes since it's my first answer on brainly
Angle B=90degrees
let angle BAC=x degrees
then angle BCA=2x degrees
thus,
angle B+ angle BAC+ angle BCA= 180degrees .........sum of angles of triangle
90+x+2x=180
90+3x=180
3x=180-90
3x=90
dividing both sides by 3
x=30
then
angle BAC=30degrees and angle BCA=2(30)=60degrees
therefore the measures of angles of triangle ABC are 30,60 and 90 degrees
here side AC is a hypotenuse
therefore
in 30-60-90 triangle
side opposite to 30degrees is half the hypotenuse
here the side opposite to 30 degrees is side BC
therefore
BC=1/2*AC
thus
2BC=AC
thus
AC=2BC
please forgive if there are mistakes since it's my first answer on brainly
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