Question

ABC is a right triangle at B and tan A= 4/3. If AC= 15cm find the lengths of AB and BC. ​

Answer 1

Answer:

as tanA=34⇒ABBC=34⇒AB=43BC

Now, in △ABC

AB2+BC2=AC2

⇒(43BC)2+BC2=152

⇒1625BC2=152

⇒BC2=52152×42

⇒BC=12

Therefore, Answer is 12 cm

Answer 2

Continue ...

BC = 12

$AB = \frac{3}{4} BC$

$AB = \frac{3}{4} \times 12$

$AB = 3 \times 3$

$AB = 9$

I hope it helps u bunny ^_^♡♡