Question

ABC is a right triangle in which C= 900

and CD AB. If BC =a, CA=b, AB=c and CD =p, then

prove that i) cp= ab

Answer 1

Answer:

Let CD⊥AB. Then, CD=p

∴ Area of ΔABC=21(Base×Height)

=21(AB×CD)=21cp

Also,

Area of ΔABC=21(BC×AC)=21ab

∴21cp=21ab

⇒cp=ab