Question

ABC is a right triangle in which is a right angle, AB = 1, AC = 2, and BC = .

cos C × sin A =

Answer 1

please mention it which is right angle

Answer 2

p= AB= 1cm h= AC=2cm b= BC= root over of (2)^2 -(1)^2           = root over of 4 - 1           = root over of 3 Thus, b = root over of 3 Cos C= BC/AC =root 3/2 Sin A =BC/AC = root 3/2  Cos C × Sin A = root 3/2 × root 3/2 = 3/4   Hope it may help you