Question

∆ABC is a right triangle, right angled at A and AD ⊥ BC. If AB = c and AC = b, then AD is equal to

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Answer 1

Answer:

Let CD⊥AB. Then, CD=p

∴ Area of ΔABC=21(Base×Height)

=21(AB×CD)=21cp

Also,

Area of ΔABC=21(BC×AC)=21ab

∴21cp=21ab

⇒cp=ab

(ii) Since ΔABC is a right triangle, right angled at C.

∴AB2=BC2+AC2

⇒c2=a2+b2

⇒(pab)2=a2+b2[∵cp=ab⇒c=pab]

⇒p2

Answer 2

Answer:

(a) bc/√b2+c2

Step-by-step explanation:

BC= √b2+c2

∆ABC~∆ACD

therefore,

AD/AB=AC/BC

AD=AC*AB/BC

=b*c/√b2+c2

=bc/√b2+c2