Question

ABC is a right triangle right angled at A such that AB = AC and bisector of ZC intersects the side AB at D. Prove that AC+AD = BC.​

Answer 1

Answer:

AC^2+AB^2 = BC^2

∵ AB=AC

∴ BC^2 = 2AC^2

BC = 1.414 AC

AD = AC tan 22.5° = 0.414 AC

AC + AD = AC + 0.414 AC = 1. 414 AC = BC

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Step-by-step explanation:

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Answer 2

here is your answer

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