ABC is a right triangle right angled at A with AB=6cm and AC=8 cm. A circle with centre O has been inscribed inside the triangle . Find the radius of the inscribing circle.
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Answered by
83
Hey mate..
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In right triangle BAC,
BC2 = AB2 + AC2 [By Pythagoras theorem]
= 62 + 82
= 36 + 64
= 100
Hence , BC = 10 cm
Semi-perimeter, s = (a + b + c)/2
= (6 + 8 + 10)/2 = 12 cm
Area of right triangle ABC = (1/2) x AB x AC
= (1/2) x 6 x 8 = 24 sq.cm
We know that, area of triangle = r x s
I.e. 24 = r x 12
Therefore, r = 2 cm
Hope it helps !!!
========
In right triangle BAC,
BC2 = AB2 + AC2 [By Pythagoras theorem]
= 62 + 82
= 36 + 64
= 100
Hence , BC = 10 cm
Semi-perimeter, s = (a + b + c)/2
= (6 + 8 + 10)/2 = 12 cm
Area of right triangle ABC = (1/2) x AB x AC
= (1/2) x 6 x 8 = 24 sq.cm
We know that, area of triangle = r x s
I.e. 24 = r x 12
Therefore, r = 2 cm
Hope it helps !!!
Answered by
60
Radius of the inscribed circle is 2 cm.
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