Question

ABC is a right triangle right angled at A with AB=6cm and AC=8 cm. A circle with centre O has been inscribed inside the triangle . Find the radius of the inscribing circle.

Answer 1

Hey mate..
========

In right triangle BAC,

BC2 = AB2 + AC2 [By Pythagoras theorem]

= 62 + 82

= 36 + 64

= 100

Hence , BC = 10 cm

Semi-perimeter, s = (a + b + c)/2

= (6 + 8 + 10)/2 = 12 cm

Area of right triangle ABC = (1/2) x AB x AC

= (1/2) x 6 x 8 = 24 sq.cm

We know that, area of triangle = r x s

I.e. 24 = r x 12

Therefore, r = 2 cm

Hope it helps !!!

Answer 2

Radius of the inscribed circle is 2 cm.